How to Get File Names In A Directory Using Groovy Script?

3 minutes read

To get file names in a directory using Groovy script, you can use the following code snippet:

1
2
3
4
5
6
7
def directory = new File("/path/to/directory")

def fileList = directory.listFiles()

fileList.each { file ->
    println file.getName()
}


Replace "/path/to/directory" with the actual path to the directory you want to get the file names from. This code will create a File object for the directory, list all files in the directory, and then print out the name of each file in the directory.


How to check for file name uniqueness in a directory using groovy script?

You can check for file name uniqueness in a directory using a Groovy script by looping through the files in the directory and comparing their names. Here is an example script that demonstrates how to do this:

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
def directoryPath = '/path/to/directory'

// Get a list of files in the directory
def files = new File(directoryPath).listFiles()

// Create a map to store the count of each file name
def fileMap = [:]

// Loop through the files and check for uniqueness
files.each { file ->
    def fileName = file.name
    if (fileMap.containsKey(fileName)) {
        fileMap[fileName]++
    } else {
        fileMap[fileName] = 1
    }
}

// Check for duplicate file names
def duplicateFiles = fileMap.findAll { it.value > 1 }

if (duplicateFiles) {
    println "Duplicate file names found:"
    duplicateFiles.each { fileName, count ->
        println "File name: $fileName, Count: $count"
    }
} else {
    println "All file names are unique"
}


Replace /path/to/directory with the actual path to the directory you want to check for file name uniqueness in. This script will loop through the files in the directory, count the occurrences of each file name, and then output any duplicate file names found.


How to filter out specific file names in a directory using groovy script?

You can filter out specific file names in a directory using a Groovy script by first obtaining a list of all files in the directory and then applying a filter to exclude the specific file names you want to exclude. Here is an example script to achieve this:

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
import java.nio.file.*

def directory = new File('/path/to/directory')

def excludedFileNames = ['file1.txt', 'file2.txt'] // List of file names to exclude

def filteredFiles = directory.listFiles().findAll { file ->
    !excludedFileNames.contains(file.name)
}

filteredFiles.each { file ->
    println file.name
}


In this script, we first define the directory path and the list of specific file names to exclude. We then use the listFiles() method to obtain a list of all files in the directory and apply the findAll method to filter out the files whose names are included in the excludedFileNames list. Finally, we iterate over the filtered files and print their names.


You can customize the script by changing the directory path and the excluded file names to suit your specific requirements.


How to extract file extensions along with file names in a directory using groovy script?

You can use the following Groovy script to extract file extensions along with file names in a directory:

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
def directory = new File("/path/to/directory")

directory.eachFile { file ->
    if (file.isFile()) {
        def fileName = file.name
        def fileExtension = fileName.substring(fileName.lastIndexOf('.') + 1)
        
        println "File Name: $fileName, File Extension: $fileExtension"
    }
}


Replace "/path/to/directory" with the path to the directory you want to search for files. The script will iterate through each file in the directory, extract the file name and file extension, and print them out.


What command is used to access file names in a directory in groovy script?

In Groovy script, the listFiles() method can be used to access file names in a directory. This method is typically used on a File object representing a directory. Here is an example:

1
2
3
4
5
6
7
def directory = new File("/path/to/directory")

def files = directory.listFiles()

files.each { file ->
    println file.name
}


This script will print out the names of all files in the specified directory.

Facebook Twitter LinkedIn Telegram Whatsapp

Related Posts:

To call a groovy method using command line, you can use the groovy command with the -e flag to run a specific script or method. For example, if you have a Groovy script file called myScript.groovy with a method called myMethod, you can call it from the command...
To execute a Groovy script from a Jenkins pipeline, you need to use the script block in your pipeline code. The script block allows you to run arbitrary Groovy code within your pipeline script. Inside this block, you can write your Groovy script code that you ...
To call a Python script from Groovy, you can use the ProcessBuilder class in Groovy. First, you need to create a ProcessBuilder object with the Python executable as the command and the path to the script as arguments. Then you can use the start() method to lau...
To run an inline script in Vagrant, you can use the config.vm.provision method in your Vagrantfile. This method allows you to specify a shell script that will be executed on the virtual machine during provisioning.You can create a new shell script file and inc...
To open a file and edit its content in a Groovy script, you can use the File class provided by Groovy. First, you need to create a new File object by passing the path of the file as a parameter. Then, you can use methods like getText() to read the content of t...